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Calculate seat apportionment for legislative bodies with various methods. These methods include divisor methods (e.g. D’Hondt, Webster or Adams), largest remainder methods and biproportional apportionment.
Mit diesem R-Package können mittels verschiedener Sitzzuteilungsverfahren Wählerstimmen in Abgeordnetensitze umgerechnet werden. Das Package beinhaltet Quoten-, Divisor- und biproportionale Verfahren (Doppelproporz oder “Doppelter Pukelsheim”).
Install the package from CRAN:
Alternatively, install the development version from Github:
proporz()
distributes seats proportionally for a vector of votes according to the following methods:
library(proporz)
votes = c("Party A" = 651, "Party B" = 349, "Party C" = 50)
proporz(votes, n_seats = 10, method = "sainte-lague")
#> Party A Party B Party C
#> 7 3 0
proporz(votes, 10, "huntington-hill", quorum = 0.05)
#> Party A Party B Party C
#> 6 4 0
Biproportional apportionment (Wikipedia) is a method to proportionally allocate seats among parties and districts.
We can use the provided uri2020
data set to illustrate biproportional apportionment with biproporz()
. You need a ‘votes matrix’ as input which shows the number of votes for each party (rows) and district (columns). You also need to define the number of seats per district.
(votes_matrix <- uri2020$votes_matrix)
#> Altdorf Bürglen Erstfeld Schattdorf
#> CVP 11471 2822 2309 4794
#> SPGB 11908 1606 1705 2600
#> FDP 9213 1567 946 2961
#> SVP 7756 2945 1573 3498
(district_seats <- uri2020$seats_vector)
#> Altdorf Bürglen Erstfeld Schattdorf
#> 15 7 6 9
biproporz(votes_matrix, district_seats)
#> Altdorf Bürglen Erstfeld Schattdorf
#> CVP 5 2 2 3
#> SPGB 4 1 2 2
#> FDP 3 1 1 2
#> SVP 3 3 1 2
You can use pukelsheim()
for dataframes in long format as input data. It is a wrapper for biproporz()
. zug2018
shows an actual election result for the Canton of Zug in a dataframe. We use this data set to create input data for pukelsheim()
. The other parameters are set to reflect the actual election system.
# In this data set, parties are called 'lists' and districts 'entities'.
votes_df = unique(zug2018[c("list_id", "entity_id", "list_votes")])
district_seats_df = unique(zug2018[c("entity_id", "election_mandates")])
seats_df = pukelsheim(votes_df,
district_seats_df,
quorum = quorum_any(any_district = 0.05, total = 0.03),
winner_take_one = TRUE)
head(seats_df)
#> list_id entity_id list_votes seats
#> 1 2 1701 8108 2
#> 2 1 1701 2993 0
#> 3 3 1701 19389 3
#> 4 4 1701 14814 2
#> 5 5 1701 4486 1
#> 6 6 1701 15695 3
The apportionment scenarios vignette contains more examples.
The package provides a basic Shiny app where you can calculate biproportional apportionment on an interactive dashboard. You need to have the packages shiny
and shinyMatrix
installed.
You can use divisor methods directly:
votes = c("Party A" = 690, "Party B" = 370, "Party C" = 210, "Party D" = 10)
# D'Hondt, Jefferson or Hagenbach-Bischoff method
divisor_floor(votes, 10)
#> Party A Party B Party C Party D
#> 6 3 1 0
# Sainte-Laguë or Webster method
divisor_round(votes, 10)
#> Party A Party B Party C Party D
#> 5 3 2 0
# Adams method
divisor_ceiling(votes, 10)
#> Party A Party B Party C Party D
#> 4 3 2 1
# Dean method
divisor_harmonic(votes, 10)
#> Party A Party B Party C Party D
#> 5 2 2 1
# Huntington-Hill method
divisor_geometric(votes, 10)
#> Party A Party B Party C Party D
#> 5 3 1 1
The largest remainder method is also accessible directly:
votes = c("I" = 16200, "II" = 47000, "III" = 12700)
# Hamilton, Hare-Niemeyer or Vinton method
largest_remainder_method(votes, 20)
#> I II III
#> 4 13 3
There are other R packages available that provide apportionment functions, some with more focus on analysis. However, biproportional apportionment is missing from the pure R packages and RBazi needs rJava with an accompanying jar.
Please feel free to issue a pull request or open an issue.
These binaries (installable software) and packages are in development.
They may not be fully stable and should be used with caution. We make no claims about them.